![SOLVED:Proof of the Chain Rule If the vector function 𝐯=𝐯(t) is differentiable and the real function y=f(t) is differentiable, show that (d)/(d t) 𝐯(f(t))=𝐯^'(f(t)) f^'(t) SOLVED:Proof of the Chain Rule If the vector function 𝐯=𝐯(t) is differentiable and the real function y=f(t) is differentiable, show that (d)/(d t) 𝐯(f(t))=𝐯^'(f(t)) f^'(t)](https://cdn.numerade.com/previews/e89d319d-3956-41d3-b1e1-f642fece9b46_large.jpg)
SOLVED:Proof of the Chain Rule If the vector function 𝐯=𝐯(t) is differentiable and the real function y=f(t) is differentiable, show that (d)/(d t) 𝐯(f(t))=𝐯^'(f(t)) f^'(t)
![calculus - Chain rule proof is a bit unclear. What is epsilion in this proof? - Mathematics Stack Exchange calculus - Chain rule proof is a bit unclear. What is epsilion in this proof? - Mathematics Stack Exchange](https://i.stack.imgur.com/BTEI3.png)
calculus - Chain rule proof is a bit unclear. What is epsilion in this proof? - Mathematics Stack Exchange
![Session 36: Proof | Part B: Chain Rule, Gradient and Directional Derivatives | 2. Partial Derivatives | Multivariable Calculus | Mathematics | MIT OpenCourseWare Session 36: Proof | Part B: Chain Rule, Gradient and Directional Derivatives | 2. Partial Derivatives | Multivariable Calculus | Mathematics | MIT OpenCourseWare](http://mit.usiu.ac.ke/courses/mathematics/18-02sc-multivariable-calculus-fall-2010/2.-partial-derivatives/part-b-chain-rule-gradient-and-directional-derivatives/session-36-proof/MIT18_02SC_L12Brds_7.png)